The binding energy per nucleon of deuteron $\left({ }_1^2 \mathrm{H}\right)$ and helium nucleus $\left({…
The binding energy per nucleon of deuteron $\left({ }_1^2 \mathrm{H}\right)$ and helium nucleus $\left({ }_2^4 \mathrm{He}\right)$ is $1.1 \mathrm{MeV}$ and $7 \mathrm{MeV}$ respectively. If two deuteron nuclei react to form a single helium nucleus, then the energy released is
$13.9 \mathrm{MeV}$
$26.9 \mathrm{MeV}$
$23.6 \mathrm{MeV}$
$19.2 \mathrm{MeV}$
Solution
Energy released $=$ total binding energy of product $-$ total binding energy of reactants $\Rightarrow 28-(2 \times 2.2)=28-4.4=236 \mathrm{MeV}$