The binding energy of deuteron is 2.2 $\mathrm{MeV}$ and that of ${ }_2^4 \mathrm{He}$ is $28 \mathrm{MeV}$.…

The binding energy of deuteron is 2.2 $\mathrm{MeV}$ and that of ${ }_2^4 \mathrm{He}$ is $28 \mathrm{MeV}$. If two deuterons are fused to form one ${ }_2^4 \mathrm{He}$ then the energy released is:
  1. $30.2 \mathrm{MeV}$
  2. $25.8 \mathrm{MeV}$
  3. $23.6 \mathrm{MeV}$
  4. $19.2 \mathrm{MeV}$

Solution

Energy released $=28-2 \times 2.2 =28-4.1 =23.6 \mathrm{MeV}$

Asked in: NEET 2006

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