The binding energy of deuteron is 2.2 $\mathrm{MeV}$ and that of ${ }_2^4 \mathrm{He}$ is $28 \mathrm{MeV}$.…
The binding energy of deuteron is 2.2 $\mathrm{MeV}$ and that of ${ }_2^4 \mathrm{He}$ is $28 \mathrm{MeV}$. If two deuterons are fused to form one ${ }_2^4 \mathrm{He}$ then the energy released is:
$30.2 \mathrm{MeV}$
$25.8 \mathrm{MeV}$
$23.6 \mathrm{MeV}$
$19.2 \mathrm{MeV}$
Solution
Energy released $=28-2 \times 2.2 =28-4.1 =23.6 \mathrm{MeV}$