The average translational kinetic energy of $N_{2}$ gas molecules at $_________{}^{\circ}C$ becomes equal to the $K . E .$ of an electron accelerated from rest through a potential difference of $0.1 volt .$
(Given $k_{B} = 1.38 \times 10^{- 23} J K^{- 1})$ (Fill the nearest integer).

Question

The average translational kinetic energy of $N_{2}$ gas molecules at $_________{}^{\circ}C$ becomes equal to the $K . E .$ of an electron accelerated from rest through a potential difference of $0.1 volt .$

(Given $k_{B} = 1.38 \times 10^{- 23} J K^{- 1})$ (Fill the nearest integer).

Aicharya · Accepted Answer

Given Translation K . E . of N 2 = K . E of electron 3 2 k T = e V 3 2 &#215; 1 . 38 &#215; 10 - 23 &#160; T = 1 . 6 &#215; 10 - 19 &#215; 0 . 1 &#160;&#160; &#8658; T = 773 &#160; K T = 773 - 273 = 500 &#176; C

The average translational kinetic energy of N 2 gas molecules at _ _ _ _ _ _ _ _ _ C ∘ becomes equal…

Solution

The average translational kinetic energy of N 2 gas molecules at _ _ _ _ _ _ _ _ _ C &#8728; becomes equal…

Solution

The average translational kinetic energy of N 2 gas molecules at _ _ _ _ _ _ _ _ _ C ∘ becomes equal…