The average force applied on the wall of a closed container depends as $\mathrm{T}^{\mathrm{X}}$ where T is…
- 0.5
- 1
- 2
- 1.5
Solution
From ideal gas equation, $\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{~V}}$
When V remains constant, $P \propto T...(ii)$
From (i) and (ii) $\begin{aligned} & F \propto \mathrm{~T}^{\mathrm{x}} \\ \therefore \quad & \mathrm{x}=1 \end{aligned}$ :
Asked in: MHT CET 2024 (10 May Shift 1)
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