The assets of a person reduced in his business such that the rate of reduction is proportional to the square…
- $\frac{20}{3}$ years
- $\frac{10}{3}$ years
- $\frac{10}{9}$ years
- $\frac{20}{9}$ years
Solution
If $A$ denotes the assets at time $t$, the rate of reduction is proportional to $\sqrt{A}$, so
$\frac{dA}{dt} = -k\sqrt{A}$
Separating and integrating gives
$\int A^{-1/2}\,dA = \int -k\,dt$
$2\sqrt{A} = -kt + C$
At $t = 0$, $A = 10^6$, hence $2\sqrt{10^6} = C$, so $C = 2000$.
At $t = 3$, $A = 10^4$, giving $2\sqrt{10^4} = -3k + 2000$
$200 = -3k + 2000$
$k = 600$
The solution becomes $2\sqrt{A} = -600t + 2000$.
Set $A = 0$ for bankruptcy: $0 = -600t + 2000$, so $t = \frac{2000}{600} = \frac{10}{3}$ years.
Correct choice is B.
Asked in: MHT CET 2025 (21 April Shift 1)