The area of the triangle formed by the tangent to the curve $x y=\mathrm{a}^2$ at $\left(x_1, y_1\right)$ on…
- $a^2$ sq. units
- $\frac{3 a^2}{2}$ sq. units
- $2 a^2$ sq. units
- $4 a^2$ sq. units
Solution

$\begin{aligned} & \because x y=a^2 \\ & \text { eqn of tangent at } P \text { : }\end{aligned}$ $t y+\frac{x}{t}-2 a=0$ When $y=0$ : $x = 2 a t$ $A(2 a t, 0)$ When $x=0$ $y=\frac{2 a}{t}$ $\therefore B\left(0, \frac{2 a}{t}\right)$. $\therefore \triangle A B O$ if a right $\angle \triangle$ $\therefore \operatorname{ar}(\triangle A B O)=\frac{1}{2} \times \frac{2 a}{t} \times 2 a t=2 a^2$
Asked in: AP EAMCET 2022 (05 Jul Shift 2)