The area of the region bounded by y 2 = 8 x and y 2 = 16 3 - x is equal to

The area of the region bounded by y2=8x and y2=163-x is equal to
  1. 323
  2. 403
  3. 16
  4. 9

Solution

Given curves are y2=8x and y2=163-x

⇒8x=48-16x ⇒x=2, so y=±4

Required area =2∫043-y216-y28dy

=23y-y348-y32404=212-6448-6424=16  

Asked in: JEE Main 2022 (26 Jun Shift 2)

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