Mathematics › Area Under Curves › Area bounded by two curves
y-x=2,x2=y
Now, x2=2+x
⇒x2-x-2=0
⇒x+1x-2=0⇒x=-1,2
Required area=∫-122+x-x2dx
=2x+x22-x33-12
=4+2-83--2+12+13
=6-3+2-12=92 square units
Asked in: JEE Main 2021 (27 Jul Shift 2)
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