The area of the region bounded by the $y$-axis, $y=\cos x, y=\sin x$, when $0 \leq x \leq \frac{\pi}{4}$, is
- $(\sqrt{2}-1)$ sq. units
- $2(\sqrt{2}-1)$ sq. units
- $(\sqrt{2}+1)$ sq. units
- $\sqrt{2}$ sq. units
Solution
$\begin{aligned} & =\left(\frac{1}{\sqrt{2}}+\frac{1}{\sqrt{2}}\right)-(0+1) \\ & =\sqrt{2}-1\end{aligned}$Asked in: MHT CET 2022 (07 Aug Shift 1)