The area of the parallelogram, whose diagonals are 2 i ^ - j ^ + k ^ and i ^ + 3 j ^ - k ^ , is equal to

The area of the parallelogram, whose diagonals are 2i^-j^+k^ and i^+3j^-k^, is equal to
  1. 262 square units
  2. 226 square units
  3. 622 square units
  4. 262 square units

Solution

Area of parallelogram =12d→1×d→2

d→1×d→2=i^j^k^2-1113-1

=-2i^+3j^+7k^

d→1×d→2=62

Area =622 square units.

Asked in: AP EAMCET 2020 (23 Sep Shift 1)

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