The area of a rectangle is $x^{2} + 7x + 10$ sq units. If its length is $(x+5)$, what is its breadth?

The area of a rectangle is $x^{2} + 7x + 10$ sq units. If its length is $(x+5)$, what is its breadth?
  1. $x + 2$
  2. $x - 2$
  3. $x + 5$
  4. $x + 7$

Solution

Breadth $= \dfrac{x^{2}+7x+10}{x+5} = \dfrac{(x+2)(x+5)}{x+5} = x+2$.

Asked in: IMO

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