The area of a quadrilateral is $360 \text{ cm}^{2}$ and the lengths of the perpendiculars from the opposite…

The area of a quadrilateral is $360 \text{ cm}^{2}$ and the lengths of the perpendiculars from the opposite vertices to a diagonal are $10$ cm and $14$ cm. Find the length of the diagonal.
  1. $24$ cm
  2. $30$ cm
  3. $36$ cm
  4. $15$ cm

Solution

$\dfrac{1}{2} d (10+14) = 360 \Rightarrow 12 d = 360 \Rightarrow d = 30$ cm.

Asked in: IMO

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