The area (in sq. units) of the region bounded by the curves $y=4|\cos x|$ and $y=-|\cos x|$ from $x=-\frac{\pi}{2}$ to $\frac{\pi}{2}$ is

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Aicharya · Accepted Answer

Given the curve $y=4|\cos x|, y=-|\cos x|$ Required area $=\int_{-\pi / 2}^{\pi / 2}(4 \cos x-(-\cos x)) d x$ $=5 \int_{-\pi / 2}^{\pi / 2} \cos x d x=5 	imes 2 \int_0^{\pi / 2} \cos x d x$ $=10 	imes 1=10$

The area (in sq. units) of the region bounded by the curves $y=4|\cos x|$ and $y=-|\cos x|$ from…

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