The area (in sq units) of the quardilateral formed by the lines $2 x+3 y+6=0$, $2 x-3 y+6=0,2 x+3 y-6=0$ and $2 x-3 y-6=0$ is

Question

Aicharya · Accepted Answer

$\begin{gathered}	ext { Required area }=\left|\frac{(6+6) 	imes(6+6)}{2(-3)-3(2)}ight| \ =\frac{12 	imes 12}{12}=12\end{gathered}$

The area (in sq units) of the quardilateral formed by the lines $2 x+3 y+6=0$, $2 x-3 y+6=0,2 x+3 y-6=0$ and…