The area (in sq. units) of the part of the circle x 2 + y 2 = 36 , which is outside the parabola y 2 = 9 x ,…

The area (in sq. units) of the part of the circle x2+y2=36, which is outside the parabola y2=9x, is equal to
  1. 12π+33
  2. 24π+33
  3. 24π-33
  4. 12π-33

Solution

Required area

=π×62-2∫039xdx+∫3636-x2dx

=36π-6x3/23/203-2x236-x2+18sin-1x636

=36π-123-20-932+9π-3π

=24π-33 sq.units

Asked in: JEE Main 2021 (24 Feb Shift 1)

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