The area (in sq. units) of the parallelogram whose diagonals are along the vectors 8 i ^ - 6 j ^ and 3 i ^ + 4 j ^ - 12 k ^ , is:

Question

Aicharya · Accepted Answer

Let the given diagonals be d 1 &#8594; and d 2 &#8594; , then d 1 &#215; d 2 = i ^ j ^ k ^ 8 - 6 0 3 4 - 12 = 72 i ^ - - 96 j ^ + 50 k ^ d 1 &#215; d 2 = 72 2 + - 96 2 + 50 2 = 5184 + 9216 + 2500 d 2 &#215; d 2 = &#160; 16900 = 130 Area = 1 2 d 1 &#215; d 2 = 1 2 &#215; 130 = 65

The area (in sq. units) of the parallelogram whose diagonals are along the vectors 8 i ^ - 6 j ^ and 3 i ^ +…

Solution