The area (in sq. units) enclosed between the curves $y=x^2$ and $y=|x|$ is

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Given curves are

On solving Eqs. $(i)$ and $(i i)$, we get $ x=0, x=1 $ Thus, coordinates of point $B$ are $(1,1)$ $ \begin{aligned} \therefore \quad \text { Total area }=2(\text { Area of region } O A B O) \\ \quad=2 \int_0^1\left(x-x^2\right) d x \\ \quad=2\left[\frac{x^2}{2}-\frac{x^3}{3}\right]_0^1=2\left[\frac{1}{2}-\frac{1}{3}\right] \\ \quad=2 \times \frac{1}{6}=\frac{1}{3} \text { sq unit } \end{aligned} $

The area (in sq. units) enclosed between the curves $y=x^2$ and $y=|x|$ is

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