The area (in sq. units) bounded by the curves $x^2=9 y$, $(x-6)^2=9 y$ and the $X$ - axis is

Question

Aicharya · Accepted Answer

Here we have to the area of shaded region $ \text { Required Area }=\int_0^3 \frac{x^2}{9} d x+\int_3^6 \frac{(\mathrm{x}-6)^2}{9} d x $

$=\frac{1}{27}\left[x^3\right]_0^3+\frac{1}{27}\left[(x-6)^3\right]_3^6=2$

Solution