The area (in sq. units) bounded by the curve $x^2+2 x+y-3=0$, the $\mathrm{X}$-axis and the tangent at the…
The area (in sq. units) bounded by the curve $x^2+2 x+y-3=0$, the $\mathrm{X}$-axis and the tangent at the point where the curve meets the Y-axis is
- $\frac{7}{10}$
- $\frac{7}{12}$
- $\frac{6}{11}$
- $\frac{5}{11}$
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2017 (24 Apr Shift 2)
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