The area (in sq. units) bounded by $x=4, y=-4$ and $y=x$ is

The area (in sq. units) bounded by $x=4, y=-4$ and $y=x$ is
  1. $48$
  2. $32$
  3. $24$
  4. $16$

Solution


The required bounded area is $\triangle A B C$. Here $A C=8 \& B C=8$ $\therefore$ Required area $=\frac{1}{2} \times A C \times B C=\frac{1}{2} \times 8 \times 8=32$

Asked in: AP EAMCET 2023 (17 May Shift 1)

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