The area enclosed by y 2 = 8 x and y = 2 x that lies outside the triangle formed by y = 2 x , x = 1 , y = 2 2 , is equal to

Question

Aicharya · Accepted Answer

Intersection point of y 2 = 8 x &#160; &#38; &#160; y = 2 x is 0 , 0 &#160; &#38; &#160; 2 , 4 2 &#160; Area of &#8710; A B C = 1 2 2 &#183; 1 = 1 2 So required area = area between the curve y 2 = 8 x and the line y = 2 x - ar &#9651; A B C = &#8747; 0 4 8 x - 2 x d x - 1 2 = 32 2 3 - 8 2 - 1 2 = 13 2 6

The area enclosed by y 2 = 8 x and y = 2 x that lies outside the triangle formed by y = 2 x , x = 1 , y = 2…

Solution