The area, enclosed by the curves y = sin x + cos x and y = | cos x - sin x | and the lines x = 0 ,   x = π 2 , is :

Question

The area, enclosed by the curves y = sin x + cos x and y = | cos x - sin x | and the lines x = 0 , &#160; x = &#960; 2 , is :

Aicharya · Accepted Answer

A = &#8747; 0 &#960; / 2 ( ( cos x + sin x ) - | cos x - sin x | ) d x A = &#8747; 0 &#960; / 4 ( ( cos x + sin x ) - ( cos x - sin x ) ) d x + &#8747; &#960; / 4 &#960; / 2 ( ( cos x + sin x ) - ( sin x - cos x ) ) d x A = 2 &#8747; 0 &#960; / 4 sin x d x + 2 &#8747; &#960; / 4 &#960; / 2 cos x d x = 2 - 1 2 + 1 + 2 1 - 1 2 = 4 - 2 2 = 2 2 ( 2 - 1 )

The area, enclosed by the curves y = sin x + cos x and y = | cos x - sin x | and the lines x = 0 ,   x…

Solution

The area, enclosed by the curves y = sin x + cos x and y = | cos x - sin x | and the lines x = 0 , &#160; x…

Solution

The area, enclosed by the curves y = sin x + cos x and y = | cos x - sin x | and the lines x = 0 , x…