The area enclosed between the curves y 2 + 4 x = 4 and y - 2 x = 2 is

The area enclosed between the curves y2+4x=4 and y-2x=2 is
  1. 253
  2. 223
  3. 9
  4. 233

Solution

Given:

y2=-4x+4

y=2x+2

Required area

=-424-y24-y-22dy

=-422-y24-y2dy

=2y-y312-y24-42

=4-812-1--8+6412-164

=15-6

=9 sq. units

Asked in: JEE Main 2023 (24 Jan Shift 1)

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