The area enclosed between the curves $y=x|x|$ and $y=x-|x|$ is :

The area enclosed between the curves $y=x|x|$ and $y=x-|x|$ is :
  1. $\frac{4}{3}$
  2. 1
  3. $\frac{2}{3}$
  4. $\frac{8}{3}$

Solution


$A=\int_{-2}^0-x^2-2 x=\frac{4}{3}$

Asked in: JEE Main 2024 (05 Apr Shift 2)

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