The area enclosed between the curve $y=\log _e(x+e)$ and the coordinate axes is

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Aicharya · Accepted Answer

$ \begin{aligned} & 	ext { Required area }(O A B)=\int_{1-e}^0 \ln (x+e) d x \ & =\left[x \ln (x+e)-\int \frac{1}{x+e} x d xight]_0^1=1 . \end{aligned} $

The area enclosed between the curve $y=\log _e(x+e)$ and the coordinate axes is

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