The area bounded by the curve, $y=-x^2$, x-axis, $x=1$ and $x=4$, is
The area bounded by the curve, $y=-x^2$, x-axis, $x=1$ and $x=4$, is
- 21 sq. units
- 10 sq. units
- 20 sq. units
- $\frac{21}{2}$ sq. units
Solution
$-\int_1^4\left(-x^2\right) \mathrm{d} x=\left[\frac{x^3}{3}\right]_1^4=\frac{64}{3}-\frac{1}{3}=21$ sq. units

Asked in: MHT CET 2022 (08 Aug Shift 1)
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