The area bounded by $y-1=-|x|$ and $y+1=|x|$ is
- $\frac{1}{2}$
- 1
- 2
- 0
Solution

Here, $\mathrm{AC}=\sqrt{1+1}=\sqrt{2}$ Area of ACBD $=4$ Area of AOC $=4 \times \frac{1}{2} \times O \mathrm{OAOC}=4 \times \frac{1}{2} \times 1 \times 1=2$ $\therefore$ Area of the required bounded region is 2
Asked in: AP EAMCET 2023 (18 May Shift 2)