The approximate value of $\sqrt[3]{0 \cdot 026}$ is
- 0.2762
- 0.2963
- 0.2632
- 0.2692
Solution
Here, $\mathrm{a}=0.027$ and $\mathrm{h}=-0.001$ $\begin{aligned} & \therefore \quad f(a)=f(0.027)=(0.027)^{\frac{1}{3}}=0.3 \text { and } \\ & \mathrm{f}^{\prime}(\mathrm{a})=\mathrm{f}^{\prime}(0.027) \\ & =\frac{1}{3(0.027)^{\frac{2}{3}}} \\ & =\frac{1}{3(0.09)}=\frac{1}{0.27} \\ & \therefore \quad \mathrm{f}(\mathrm{a}+\mathrm{h}) \approx \mathrm{f}(\mathrm{a})+\mathrm{hf}^{\prime}(\mathrm{a}) \\ & \approx 0.3-\frac{0.001}{0.27} \\ & \approx 0.3-0.0037 \\ & \approx 0.2963 \end{aligned}$
Asked in: MHT CET 2024 (02 May Shift 2)
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