The angular speed of truck wheel is increased from 900   rpm to 2460   rpm in 26 seconds. The…

The angular speed of truck wheel is increased from 900 rpm to 2460 rpm in 26 seconds. The number of revolutions by the truck engine during this time is ______.

(Assuming the acceleration to be uniform).

Solution

We know, θ=ω1+ω22t

Let number of revolutions be N

2πN=2π900+246060×2×26

N=728

Asked in: JEE Main 2021 (17 Mar Shift 1)

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