The angular speed of the minute hand of a clock in degrees per second is

Question

Aicharya · Accepted Answer

The minute hand, in one hour $(=3600 \mathrm{~s})$ completes a full $360^{\circ}$ rotation. So its angular speed is given by: $\omega=\frac{\Delta \theta}{\Delta t}=\frac{360^{\circ}}{3600 \mathrm{~s}}=0.1^{\circ} \mathrm{s}^{-1}$

The angular speed of the minute hand of a clock in degrees per second is

Solution