The angular shape of the ozone molecule consists of

1. $1 \sigma$ and $1 \pi$ bonds with bond angle $109^{\circ}$
2. $2 \sigma$ and $1 \pi$ bonds with bond angle $117^{\circ}$
3. $2 \sigma$ and $2 \pi$ bonds with bond angle $120^{\circ}$
4. $1 \sigma$ and $2 \pi$ bonds with bond angle $60^{\circ}$

Solution

The structure of ozone is
So, there are $2 \sigma$ and $1 \pi$ bond with bond angle $117^{\circ}$.

Asked in: AP EAMCET 2021 (23 Aug Shift 2)

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