The angular momentum of the orbital electron is integral multiple of:

The angular momentum of the orbital electron is integral multiple of:
  1. h
  2. 2πh
  3. h2π
  4. 3πh

Solution

According to Bohr''s second postulate, an electron can only revolve in those nuclear orbits of principal quantum numbers ''n'' which have angular momentum value as equal to integral multiples of h2π.

Therefore, mvr=nh2π

Asked in: AP EAMCET 2021 (20 Aug Shift 1)

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