The angular momentum of the electron in the third Bohr orbit of hydrogen atom is ' $l$ '. Its angular…
The angular momentum of the electron in the third Bohr orbit of hydrogen atom is ' $l$ '. Its angular momentum in the fourth Bohr orbit is
- $4 l$
- $\frac{4}{3} l$
- $\frac{5}{4} l$
- $\frac{3}{2} l$
Solution
Angular momentum of an electron in the nth Bohr orbit of hydrogen atom,
$\begin{aligned}
& \mathrm{L}=\frac{\mathrm{nh}}{2 \pi} \\
& \Rightarrow \mathrm{~L} \propto \mathrm{n}
\end{aligned}$
$\begin{aligned} \therefore \quad \frac{\mathrm{L}_1}{\mathrm{~L}_2} & =\frac{l}{\mathrm{~L}^{\prime}}=\frac{3}{4} \\ \mathrm{~L}^{\prime} & =\frac{4}{3} l\end{aligned}$
Asked in: MHT CET 2024 (11 May Shift 2)
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