The angular momentum of electron in $\mathrm{H}$ atom in a particular $n$ state is $\frac{h}{\pi}$. What is the energy in $J$ required to excite the electron from this particular $\mathrm{n}$ state to $(\mathrm{n}+1)$ state? $\left(x=+2.18 imes 10^{-18} \mathrm{~J} ight)$

Question

The angular momentum of electron in $\mathrm{H}$ atom in a particular $n$ state is $\frac{h}{\pi}$. What is the energy in $J$ required to excite the electron from this particular $\mathrm{n}$ state to $(\mathrm{n}+1)$ state? $\left(x=+2.18 	imes 10^{-18} \mathrm{~J}ight)$

Aicharya · Accepted Answer

Since $\mathrm{L}=\frac{\mathrm{nh}}{2 \pi}=\frac{\mathrm{h}}{\pi} \Rightarrow \mathrm{n}=2 ;(\mathrm{n}+1)=3$ Thus, $\Delta \mathrm{E}=13.6\left(\frac{1}{\mathrm{n}_1^2}-\frac{1}{\mathrm{n}_2^2}ight) \mathrm{eV}$ $\begin{aligned} & =13.6\left(\frac{1}{2^2}-\frac{1}{3^2}ight) \ & =1.89 \mathrm{eV}=3.028 	imes 10^{-19} \ & =\frac{5 	imes 2.18 	imes 10^{-18}}{36} \ & =\frac{5 x}{36}\end{aligned}$

The angular momentum of electron in $\mathrm{H}$ atom in a particular $n$ state is $\frac{h}{\pi}$. What is…

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