The angular displacement of body performing circular motion is given by $ heta=5 \sin \frac{\pi t}{6}$. The angular velocity of the body at $t=3$ second will be $\left[\sin \frac{\pi}{2}=1, \cos \frac{\pi}{2}=0 ight]$

Question

The angular displacement of body performing circular motion is given by $	heta=5 \sin \frac{\pi t}{6}$. The angular velocity of the body at $t=3$ second will be $\left[\sin \frac{\pi}{2}=1, \cos \frac{\pi}{2}=0ight]$

Aicharya · Accepted Answer

$\begin{aligned} & 	heta=5 \sin \frac{\pi t}{6} \ & 	herefore \frac{\mathrm{d} 	heta}{\mathrm{dt}}=\frac{\pi}{6} \cdot 5 \cos \frac{\pi \mathrm{t}}{6} \ & 	ext { At } \mathrm{t}=3 \mathrm{~s}, \frac{\mathrm{d} 	heta}{\mathrm{dt}}=\frac{5 \pi}{6} \cos \frac{\pi 	imes 3}{6}=\frac{5 \pi}{6} \cos \frac{\pi}{2}=0\end{aligned}$

The angular displacement of body performing circular motion is given by $\theta=5 \sin \frac{\pi t}{6}$. The…

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