The angle of projection for a projectile to have same horizontal range and maximum height is :

Question

Aicharya · Accepted Answer

$\begin{aligned} & \frac{\mathrm{u}^2 \sin 2 	heta}{\mathrm{g}}=\frac{\mathrm{u}^2 \sin ^2 	heta}{2 \mathrm{~g}} \ & 4 \sin 	heta \cos 	heta=\sin ^2 	heta \ & 4=	an 	heta\end{aligned}$

The angle of projection for a projectile to have same horizontal range and maximum height is :

Solution