The angle of polarisation for a medium with respect to air is $60^{\circ}$. The critical angle of this medium with respect to air is

Question

Aicharya · Accepted Answer

Angle of polarisation, $\mathrm{i}_{\mathrm{p}}=60^{\circ}$ $	herefore \quad \mu=	an \mathrm{i}_{\mathrm{p}}=	an 60^{\circ}=\sqrt{3}$ $	herefore \quad$ Critical angle, $C=\sin ^{-1}\left(\frac{1}{\mu}ight)=\sin ^{-1}\left(\frac{1}{\sqrt{3}}ight)$

The angle of polarisation for a medium with respect to air is $60^{\circ}$. The critical angle of this…

Solution