The angle between two lines $\frac{x+1}{2}=\frac{y+3}{2}=\frac{z-4}{-1}$ and…
The angle between two lines $\frac{x+1}{2}=\frac{y+3}{2}=\frac{z-4}{-1}$ and $\frac{x-4}{1}=\frac{y+4}{2}=\frac{z+1}{2}$ is
- $\cos ^{-1}\left(\frac{4}{9}\right)$
- $\cos ^{-1}\left(\frac{2}{9}\right)$
- $\cos ^{-1}\left(\frac{1}{9}\right)$
- $\cos ^{-1}\left(\frac{5}{9}\right)$
Solution
The required angle
$\begin{aligned} & \theta=\cos ^{-1}\left(\frac{2 \times 1+2 \times 2+(-1) \times 2}{\sqrt{2^2+2^2+1^2} \cdot \sqrt{1^2+2^2+2^2}}\right) \\ & \Rightarrow \theta=\cos ^{-1}\left(\frac{4}{3 \times 3}\right) \\ & \Rightarrow \theta=\cos ^{-1}\left(\frac{4}{9}\right)\end{aligned}$
Asked in: MHT CET 2022 (07 Aug Shift 1)
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