The angle between the straight lines represented by $\left(x^2+y^2\right) \sin ^2 \alpha=(x \cos \alpha-y…
The angle between the straight lines represented by $\left(x^2+y^2\right) \sin ^2 \alpha=(x \cos \alpha-y \sin \alpha)^2$ is
- $\frac{\alpha}{2}$
- $\alpha$
- $2\alpha$
- $\frac{\pi}{2}$
Solution
No solution. Refer to answer key.
Asked in: AP EAMCET 2015
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