The angle between the circles $x^2+y^2+4 x-14 y+28=0$ and $x^2+y^2-12 x-6 y-4=0$ is

The angle between the circles $x^2+y^2+4 x-14 y+28=0$ and $x^2+y^2-12 x-6 y-4=0$ is
  1. $60^{\circ}$
  2. $\cos ^{-1} \frac{3}{35}$
  3. $45^{\circ}$
  4. $\cos ^{-1}\left(\frac{2}{\sqrt{5}}\right)$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (24 Apr Shift 2)

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