The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity $53.1 {Wm}^{- 2}$ is
(Permittivity of free space $= 8.85 \times 10^{- 12} C^{2} N^{- 1} m^{- 2}$ )

Question

The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity 53 . 1 Wm - 2 is (Permittivity of free space = 8 . 85 &#215; 10 - 12 C 2 &#160; N - 1 m - 2 )

Aicharya · Accepted Answer

The expression for the electromagnetic wave is,

$I = \frac{1}{2} ε_{0} E_{0}^{2} c$

Rewrite the above equation.

$E_{0} = \sqrt{\frac{2 I}{ε_{0} c}}$

Substitute the values in the above equation.

$E_{0} = \sqrt{\frac{2 \times 53.1}{8.85 \times 10^{- 12} \times 3 \times 10^{8}}} = 200 N C^{- 1}$

The amplitude of the electric field in a parallel beam of plane electromagnetic waves of intensity 53 . 1 Wm…

Solution