The amplitude of electric field in an electromagnetic wave is $60 \mathrm{Vm}^{-1}$. Then the amplitude of…

The amplitude of electric field in an electromagnetic wave is $60 \mathrm{Vm}^{-1}$. Then the amplitude of magnetic field is
  1. $2 \times 10^{-7} \mathrm{~T}$
  2. $2 \times 10^7 \mathrm{~T}$
  3. $6 \times 10^7 \mathrm{~T}$
  4. $6 \times 10^{-7} \mathrm{~T}$

Solution

$\begin{aligned} & B_0=\frac{E_0}{c} \quad\left[\because c=3 \times 10^8 \mathrm{~m} / \mathrm{s}\right] \\ & =\frac{60}{3 \times 10^8}=20 \times 10^{-8}=2 \times 10^{-7} \mathrm{~T}\end{aligned}$

Asked in: AP EAMCET 2017 (26 Apr Shift 1)

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