The amplitude of a wave represented by displacement equation $y = \frac{1}{\sqrt{a}} \sin \omega t \pm \frac{1}{\sqrt{b}} \cos \omega t$ will be

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Aicharya · Accepted Answer

Displacement, $y = \frac{1}{\sqrt{a}} \sin \omega t \pm \frac{1}{\sqrt{b}} \sin \left(\omega t + \frac{\pi}{2}ight)$ Here, phase difference $= \frac{\pi}{2}$ $	herefore$ The resultant amplitude $= \sqrt{\left(\frac{1}{\sqrt{a}}ight)^2 + \left(\frac{1}{\sqrt{b}}ight)^2} = \sqrt{\frac{1}{a} + \frac{1}{b}} = \sqrt{\frac{a + b}{ab}}$

The amplitude of a wave represented by displacement equation $y = \frac{1}{\sqrt{a}} \sin \omega t \pm…

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