The amount of work done to break a big water drop of radius ' $R$ ' into 27 small drops of equal radius is 10 J. The work done required to break the same big drop into 64 small drops of equal radius will be

Question

Aicharya · Accepted Answer

$\begin{aligned}
& W_1=s 4 \pi\left(\frac{R}{3}\right)^2 \times 27-4 \pi R^2 \cdot s \\ & \Rightarrow W_1=4 \pi R^2 \cdot s(2)=10 \text { Joule }
\end{aligned}$
Now, $W_2=s 4 \pi R^2(4-1)=4 \pi R^2 s \times 3$
$\Rightarrow \quad W_2=3 \times \frac{10}{2}=15 \text { Joule }$

The amount of work done to break a big water drop of radius ' $R$ ' into 27 small drops of equal radius is…

Solution