The amount of water produced ( in   g ) in the oxidation of 1 mole   of rhombic sulphur by conc. H…

The amount of water produced (in g) in the oxidation of 1 mole of rhombic sulphur by conc. HNO3 to a compound with the highest oxidation state of sulphur is
(Given data: Molar mass of water=18 g mol-1 )

Solution

S8+48HNO3→8H2SO4+48NO2+16H2O
∵ 1 mol of S8 produces 16 mole of H2O;
∴ Mass of H2O produced ⇒16×18
⇒288 g

Asked in: JEE Advanced 2019 (Paper 2)

Practice more p Block Elements (Group 15, 16, 17 & 18) questions on Aicharya