The amount of sugar C 12 H 22 O 11 required to prepare 2 L of its 0 .1   M aqueous solution is:

The amount of sugar C12H22O11 required to prepare 2L of its 0.1 M aqueous solution is:
  1. 17.1 g
  2. 136.8 g
  3. 68.4 g
  4. 34.2 g

Solution

Molarity=MolesVolume in L

⇒0.1=moles2

Moles of sucrose required =2×0.1=0.2 moles

Weight of sucrose=0.2×342 g=68.4 g

Asked in: JEE Main 2019 (10 Jan Shift 2)

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