The amount of ice that will separate on cooling a solution containing $50 \mathrm{~g}$ of ethylene glycol in…

The amount of ice that will separate on cooling a solution containing $50 \mathrm{~g}$ of ethylene glycol in $200 \mathrm{~g}$ water to $-9.3^{\circ} \mathrm{C}$ is $\left[\mathrm{K}_{\mathrm{f}}=1.86 \mathrm{~K}ight.$ molality $\left.^{-1}ight]$
  1. $38.71 \mathrm{~g}$
  2. $38.71 \mathrm{~mg}$
  3. $42 \mathrm{~g}$
  4. $42 \mathrm{~mg}$

Solution

$\Delta \mathrm{T}=\frac{1000 \times \mathrm{K}_{\mathrm{f}} \times \mathrm{w}}{\mathrm{W} \times \mathrm{M}}$
or $9.3=\frac{1000 \times 1.86 \times 50}{62 \times \mathrm{W}}$
$\therefore \mathrm{W}=161.29$
$\therefore$ Ice separated $=200-161.29=38.71 \mathrm{~g}$

Asked in: JEE-TOPICTESTS-CHEMISTRY

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