The amount of energy released when $20 \mathrm{~mL}$ of $0.5 \mathrm{M} \mathrm{NaOH}$ are mixed with $100…
The amount of energy released when $20 \mathrm{~mL}$ of $0.5 \mathrm{M} \mathrm{NaOH}$ are mixed with $100 \mathrm{~mL}$ of $0.1 \mathrm{M}$
$\mathrm{HCl}$ is $\mathrm{x} \mathrm{kJ} .$ The heat of neutralisation (in $\mathrm{kJ}$ $\mathrm{mol}^{-1}$ ) is
$-100 \mathrm{x}$
$-50 \mathrm{x}$
$+100 \mathrm{x}$
$+50 x$
Solution
In question $0.01$ gev of $\mathrm{NaOH}$ is being neutralised by $0.01$ gev of $\mathrm{HCl}$ and value is $\mathrm{x} \mathrm{kJ}$, for 1 gev the value is $-100 \mathrm{x}$ (exothermic process).