The amount of calcium oxide produced on heating 150 kg limestone ( $75 \%$ pure) is ______ kg. (Nearest…

The amount of calcium oxide produced on heating 150 kg limestone ( $75 \%$ pure) is ______ kg. (Nearest integer)
Given : Molar mass (in $\mathrm{g} \mathrm{mol}^{-1}$) of Ca-40, O-16, C-12

Solution

$\begin{aligned} & \mathrm{CaCO}_3 \rightarrow \mathrm{CaO}+\mathrm{CO}_2 \\ & \text { mass of } \mathrm{CaCO}_3=\frac{150 \times 75}{100}=112.5 \mathrm{~kg} \\ & =112500 \mathrm{~g} \\ & \mathrm{n}_{\mathrm{CaCO}_3}=1125 \\ & \mathrm{So} \text { moles of } \mathrm{CaO}=1125 \\ & \quad \text { mass of } \mathrm{CaO}=\frac{1125 \times 56}{1000}=63 \mathrm{~kg} \\ & \text { Correct answer } \Rightarrow 63\end{aligned}$

Asked in: JEE Main 2025 (04 Apr Shift 2)

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