The alternating current is given by, i = 42 sin 2 π T t + 10   A . The R.M.S. value of this…

The alternating current is given by, i=42sin2πTt+10 A. The R.M.S. value of this current is __________ A.

Solution

The given function of current is, i=42sin2πTt+10 A

It means,  i2=42sin22πtT+100+2042sin2πtT

i2=422+100

RMS value of the current is, irms=i2=121=11 A

Asked in: JEE Main 2021 (27 Aug Shift 1)

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